If an object of mass 2 kg is dropped from a height of 10 metres, what will be the ratio of its potential energy and kinetic energy at the height of 5 metres (g=10m/sec2)
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Correct answer: A
Explanation
The correct answer is option 1 i.e. 1:1.
To find the ratio of potential energy (PE) and kinetic energy (KE) of a 2 kg object at a height of 5 meters, we can use the following formulas:
PE = mgh
At 5 meters, PE = 2 × 10 × 5 = 100 Joules.
KE = ½ mv²
The total initial PE when the object is at 10 meters is 2 × 10 × 10 = 200 Joules. The loss in height is 5 meters, so the kinetic energy at 5 meters is 200 - 100 = 100 Joules.
Thus, the ratio of PE to KE at 5 meters is 1:1.