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SSC Selection Post 2023 PYQ — Question 64

SSC Selection Post - Graduation Level - 30 June 2023 - Shift 1 • Quantitative Aptitude • Q64

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If ab + bc + ca = 0, then find the value of 1a2−bc+1b2−ca+1c2−ab {{1} \over a^2-bc}+ {{1} \over b^2-ca}+ {{1} \over c^2-ab}

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Correct answer: A

Explanation

The correct answer is Option 1 i.e. 0.

1/(a2 - bc) + 1/(b2 - ca) + 1/(c2 - ab)

= 1/[a(a + b + c)] + 1/[b(a + b + c)] + 1/[c(a + b + c)]

= (bc + ac + ab)/[abc(a + b + c)]

= 0/[abc(a + b + c)]

= 0