If a4 + b4 + a2b2 = 273 and a2 + b2 - ab = 21, then one of the values of
is :
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. -
a4 + b4 + a2b2 = 273,
(a2)2 + (b2)2 + 2 a2b2 - a2b2 = 273
(a2 + b2)2 = 273 + a2b2 ..............(1)
a2 + b2 - ab = 21
a2 + b2 = 21 + ab ......................(2)
On putting the value of eq 2 in eq 1 we get,
441 + a2b2 + 42ab = 273 + a2b2
42ab = 273 - 441
ab = -4.........................(3)
a2 + b2 - ab = 21
on adding 2ab on both sides we get,
a2 + b2 + 2ab = 21 + 3ab
(a + b)2 = 21 + 3 × -4 = 9
a + b = +3 and -3.
If a + b = +3 then 1/a + 1/b = -3/4.
If a + b = -3 then 1/a + 1/b = -3/-4 = 3/4.