If a² + b² + c² = ab + bc + ca, then the value of 11a ⁴+ 13b ⁴ + 15c ⁴over 16a ² b ² + 19b ² c ² + 17c ² a ² is:

If a² + b² + c² = ab + bc + ca, then the value of 11a ⁴+…

If a² + b² + c² = ab + bc + ca, then the value of $11a ^ 4+ 13b ^ 4 + 15c ^ 4\over 16a ^ 2 b ^ 2 + 19b ^ 2 c ^ 2 + 17c ^ 2 a ^ 2$ is:

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Correct answer: C

Explanation

The correct answer is option 3 i.e. ${3\over4}$ .

According to the given question,

$11a ^ 4+ 13b ^ 4 + 15c ^ 4\over 16a ^ 2 b ^ 2 + 19b ^ 2 c ^ 2 + 17c ^ 2 a ^ 2$

Put a = b = c = 1,

⇒ (11 + 13 + 15)/(16 + 19 + 17)

⇒ 39/52 = 3/4