If a²+ b² + c²= ab + bc + ac, then the value of (11 a⁴+13 b⁴ + 17 c⁴)/(17 a²b+9bc² + 15 c²a) is.

If a²+ b² + c²= ab + bc + ac, then the value of (11 a⁴+13…

If a²+ b² + c²= ab + bc + ac, then the value of $\frac{11 a^4+13 b^4 + 17 c^4}{17 a^2b+9bc^2 + 15 c^2a}$ is.

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Correct answer: A

Explanation

The correct answer is Option 1 i.e. 1.

Let,

The value of a = 1, b = 1, and c = 1

Thus, the value of $\frac{11 a^4+13 b^4 + 17 c^4}{17 a^2b+9bc^2 + 15 c^2a}$

⇒ $\frac{11 (1)^4+13 (1)^4 + 17 (1)^4}{17 (1)^2(1)+9(1)(1)^2 + 15 (1)^2(1)}$ = $\frac{11 +13 + 17}{17 +9+ 15 }$ = $\frac{41}{41}$ = 1