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SSC CGL 2020 PYQ — Question 52

SSC CGL - 9th March 2020 Shift 2 • Quantitative Aptitude • Q52

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If a2 + b2 + c2 = 0, then the value of (2(a6 + b6 + c6)) / (3a2b2c2) is:

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Correct answer: B

Explanation

The correct answer is option 2 i.e 2

⇒ a2 + b2 + c2 = 0

We know that

⇒ x + y + z = 0 ⇔ x3 + y3 + z3 = 3xyz

Let x = a2, y = b2, c = z2

⇒ a6 + b6 + c6 = 3a2b2c2

⇒  (2(a6 + b6 + c6)) / (3a2b2c2)

⇒  (6a2b2c2) / (3a2b2c2)

⇒ 2