SSC CGL 2024 PYQ — Question 61

The correct answer is option 2 i.e. 704 cm².

Volume of cone =${1 \over 3} \pi r^2 h$

⇒ 1232 = ${1 \over 3} \times {22 \over 7} \times r^2 \times 24$

⇒ r² = 7 × 7

⇒ r = 7 cm

Now, l² = r² + h² 

⇒ l² = 7² + 24² = 49 + 576 = 625

⇒ l = 25 cm

TSA of cone = $\pi r (l + r)$

= ${22 \over 7}\times 7 (25 + 7)$

= 22 × 32 = 704