If a natural number, when divided by 5, 6, and 7, leaves a remainder of 4, in each case, then what is the smallest possible three-digit natural number?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 214.
Given that,
A number is divided by 5, 6, and 7 and leaves the remainder of 4
We know that,
The smallest possible three-digit number = LCM (5, 6, 7) + remainder
Now,
The smallest possible three-digit number is LCM (5, 6, 7) + remainder
⇒ 5 × 6 × 7 + 4
⇒ 210 + 4 = 214