If a natural number, when divided by 2, 3, and 4, leaves a remainder of 1 in each case, then what is the smallest possible three-digit natural number?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 109.
Given that,
If a natural number, when divided by 2, 3, and 4, leaves a remainder of 1, in each case
LCM (2, 3, and 4) = 12
Let the smallest 3-digit number be 100
Now,
⇒ 100/12
⇒ Remainder 4
Hence,
The required three-digit number = 100 + (12 - 4) + 1 = 100 + 8 + 1 = 109