If a man's present age is twice what it was 10 years ago, what is his current age?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 20.
According to the question:
Present age is twice the age 10 years ago
So, x = 2(x − 10)
x = 2x − 20
x − 2x = −20
−x = −20
x = 20
Thus, the man's present age is 20 years.