SSC CHSL 2025 PYQ — Question 54

SSC CHSL - 27 Nov 2025 - Shift 3 • Quantitative Aptitude • Q54

If a car reduces its speed by 10 km/h, it takes 1 hour more for a journey of 300 km. Find original speed.

Show answer & explanation

Correct answer: B

Explanation

Given:

Distance = 300 km

Reducing speed by 10 km/h results in 1 hour more time

Formula:

Time = Distance / Speed

Let initial speed = x km/h

Initial time = 300 / x

New speed = x − 10

New time = 300 / (x − 10)

Conditionally:

300/(x − 10) − 300/x = 1

LCM = x(x − 10)

300x − 300(x − 10) = x(x − 10)

300x − 300x + 3000 = x² − 10x

x² − 10x − 3000 = 0

x² − 60x + 50x − 3000 = 0

x(x − 60) + 50(x − 60) = 0

(x − 60)(x + 50) = 0

x = 60 km/h