If a + b + c = 9 and ab + bc + ca = -22, then the value of a3 + b3 +c3 - 3abc is :
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e 1323
Explanation:
⇒ a + b + c = 9
⇒ ab + bc + ca = -22
We need to find the value of a3 + b3 + c3- 3abc
We know,
⇒ a3 + b3 + c3- 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)
Now we need to find the value of a2 + b2 + c2
We also know,
⇒ (a + b + c)2 = a2 + b2 + c2 + 2( ab + bc + ca )
Putting the value of a + b + c = 9 and ab + bc + ca = -22
⇒ (9)2 = a2 + b2 + c2 + 2(-22)
⇒ 81 = a2 + b2 + c2 -44
⇒ a2 + b2 + c2 = 81 + 44
⇒ a2 + b2 + c2 = 125
Now,
Substituting value in the formula for a³ + b³ + c³- 3abc
⇒ a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)
⇒ a3 + b3 + c3 - 3abc = (a + b + c) (a2 + b2 + c2 - (ab + bc + ca))
⇒ a3 + b3 + c3 - 3abc = (9)(125 + 22)
⇒ a3 + b3 + c3 - 3abc = (9)(147)
⇒ a3 + b3 + c3 - 3abc = 1323