SSC CGL 2020 PYQ — Question 67

SSC CGL - 6th March 2020 Shift 1 • Quantitative Aptitude • Q67

If a + b + c = 9 and ab + bc + ca = -22, then the value of a3 + b3 +c3 - 3abc is :

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e 1323

Explanation:

⇒ a + b + c = 9

⇒ ab + bc + ca = -22

We need to find the value of a3 + b3 + c3- 3abc

We know,

⇒ a3 + b3 + c3- 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)

Now we need to find the value of a2 + b2 + c2

We also know,

⇒ (a + b + c)2 = a2 + b2 + c2 + 2( ab + bc + ca )

Putting the value of a + b + c = 9 and ab + bc + ca = -22

⇒ (9)2 = a2 + b2 + c2 + 2(-22)

⇒ 81 = a2 + b2 + c2 -44

⇒ a2 + b2 + c2 = 81 + 44

⇒ a2 + b2 + c2 = 125

Now,

Substituting value in the formula for a³ + b³ + c³- 3abc

⇒ a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)

⇒ a3 + b3 + c3 - 3abc = (a + b + c) (a2 + b2 + c2 - (ab + bc + ca))

⇒ a3 + b3 + c3 - 3abc = (9)(125 + 22)

⇒ a3 + b3 + c3 - 3abc = (9)(147)

⇒ a3 + b3 + c3 - 3abc = 1323