If a + b + c = 6, a² + b²+c² = 30 and a3 + b³ + c3 = 165, then the value of 4abc is:
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Correct answer: C
Explanation
The correct answer is Option 3 i.e. 1.
a + b + c = 6,
a² + b²+c² = 30,
a3 + b³ + c3 = 165
ab + bc + ca = (36 − 30)/2 = 3
a³ + b³ + c³ = 216 − 18×3 + 3abc = 165
⇒ 3abc = 165 − 162 = 3 ⇒ abc = 1