If (a + b - c) = 20, and a2 + b2 + c2 = 152, find the value of a3 + b3 - c3 + 3abc.
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Correct answer: D
Explanation
The correct answer is option 4 i.e. 560.
Let the value of c = 0
Now, a + b = 20 ...(i)
And a2 + b2 = 152
Squarying both sides of equation (i),
⇒ a2 + b2 + 2ab = 400
⇒ 2ab = 400 - 152
⇒ ab = 124
Now, given expression = a3 + b3 (putting c = 0)
Now, a3 + b3 = (a + b)3 - 3ab(a + b)
⇒ 203 - 3(124)(20)
⇒ 8000 - 7440 = 560