SSC CHSL 2023 PYQ — Question 61

SSC CHSL - 07 Aug 2023 - Shift 1 • Quantitative Aptitude • Q61

If a + b + c = 15 and ab + bc + ca = 22, then find the value of a2 + b2 + c2.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 181.

(a + b + c)2 =  a2 + b2 + c2 + 2(ab + bc + ca)

According to the given question,

⇒ 152 =  a2 + b2 + c2 + 2(22)

⇒ 225 =  a2 + b2 + c2 + 44

⇒ a2 + b2 + c2 = 225 - 44

⇒ a2 + b2 + c2 = 181