If a + b + c = 11, ab + bc + ca = 3 and abc = -135, then what is the value of a3 + b3 + c3 ?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e 827.
| Understanding/Application |
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a3 + b3 + c3 = (a + b + c) [(a2 + b2 + c2) -3(ab + bc + ac)] + 3abc = (11)[(11)2 - 3(3)] + 3 × (-135) |
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= (11)[112] - 405 = 1232 - 405 = 827 |