If a + b + c = 0, then find the value of (a²+b²+c²)/(a²-bc)

If a + b + c = 0, then find the value of $\frac{a^2+b^2+c^2}{a^2-bc}$

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 2.

a + b + c = 0

let's assume the value of a = 1, b = 1, c = -2

So, the value of $\frac{a^2+b^2+c^2}{a^2-bc}$ = (1 + 1 + 4)/(1 + 2) = 6/3 = 2

SSC CHSL 2022 PYQ — Question 66