SSC CHSL 2020 PYQ — Question 69

SSC CHSL - 12th October 2020 - Shift 2 • Quantitative Aptitude • Q69

If a - b = 4 and a3 - b3 = 88, then find the value of a2 - b2.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e 8√(6).

Understanding Application

(a3 - b3)=( a - b)( a2 - b2 + ab)

(a3 - b3)=(a - b){ (a - b)2 + ab}

Given, a - b = 4 and a3 - b3 = 88.

(a2 + b2)2(a2 - b2)2 = 4a2b2

(a3 - b3)=(a - b){ (a - b)2 + ab}

88 = 4 x {(4)2 + 3ab}

22= 16 +3ab

3ab = 22 - 16 = 6

ab = 2

(a - b)2 = a2 + b2 -2ab 

42 = a2 + b2 -2 x 2

a2 + b2=16 + 4 = 20

 

(a2 + b2)2 - (a2 - b2)2 = 4a2b2

(20)2 -  (a2 - b2)2 = 4 x 22

(a2 - b2)2 = 400 - 16 = 384

(a2 - b2)=384\sqrt384

(a2 - b2) = 868 \sqrt 6