SSC CHSL 2022 PYQ — Question 53

SSC CHSL - 3 June 2022 - Shift 2 • Quantitative Aptitude • Q53

If a - b = 3 and a3 - b3 = 999, then Find the value of a2 - b2.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 63.

a - b = 3 and a3 - b3 = 999

a3 - b3 = (a - b) {(a - b)2 + 3ab}

⇒ 999 = 3(9 + 3ab)

⇒ 324/3 = ab

ab = 108

(a + b)2 = (a - b)2 + 4ab

⇒ (a + b)2 = 9 + 4 × 108

⇒ (a + b)2 = 441

⇒ a + b = 21

a2 - b2 = (a + b)(a - b) = 3 × 21 = 63