SSC CHSL 2025 PYQ — Question 51

SSC CHSL - 19 Nov 2025 - Shift 2 • Quantitative Aptitude • Q51

If (a + b)² = 121 and ab = 10, then find a² + b².

Show answer & explanation

Correct answer: C

Explanation

Given:

(a + b)² = 121

ab = 10

By the formula:

(a + b)² = a² + b² + 2ab

121 = a² + b² + 2 × 10

121 = a² + b² + 20

a² + b² = 121 − 20

a² + b² = 101