If a 9-digit number 609a5b9c9 is divided by 99, then (a + b + c) is equal to:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 16.
Sum of digits = 6 + 0 + 9 + a + 5 + b + 9 + c + 9 = 38 + a + b + c
For divisibility by 9: 38 + a + b + c must be divisible by 9
If a + b + c = 16 then, 38 + a + b + c = 54 (Divisible by 9)
Also, (6 + 9 + 5 + 9 + 9) - (0 + a + b + c) = 38 - (a + b + c)
For divisibility by 11: 38 - (a + b + c) must be divisible by 11
If a + b + c = 16 then, 38 - (a + b + c) = 22 (Divisible by 11)
Hence, a + b + c = 16
