SSC CGL 2019 PYQ — Question 72

SSC CGL - 6th June 2019 - Shift 2 • Quantitative Aptitude • Q72

If a 9-digit number 32x4115y2 is divisible by 88, then the value of (4x – y) for the smallest possible value of y is:

Show answer & explanation

Correct answer: C

Explanation

Correct Answer is option 3 i.e. 31

Concept

Understanding

Application

For divisibility by 88, number should be divisible by 11 and 8 both.

32x4115y2 is divisible by 88

For divisible by 8 last 3 digit of the number (5y2) must be divisible by 8.

So, the value of y can be 1,5 and 9.

For divisibility by 11, difference of sum of digits at odd place and sum of digits at even place must be zero or divisible by 11.

So, (11+x) – (7+y) = 0 or multiple of 11

For the smallest value of y, y = 1

11 + x – 7 – 1 = 0

3 + x = 0

So,

Only one value of x that is x = 8 will satisfy the equation.

By putting y = 1 and x = 8

(4x – y) = 31