If A = 60 × [6/25÷(16/15 of3/8)+5-(1-21/12)] , then the sum of the digits of A is:

If A = 60 × [6/25÷(16/15 of3/8)+5-(1-21/12)] , then the…

If A = 60 × $[\frac{6}{25}\div(\frac{16}{15} of\frac{3}{8})+5-(1-2\frac{1}{12})]$ , then the sum of the digits of A is:

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Correct answer: C

Explanation

The correct answer is Option 3 i.e. 5.

A = 60 × $[\frac{6}{25}\div(\frac{16}{15} of\frac{3}{8})+5-(1-2\frac{1}{12})]$

⇒ A = 60 × $[\frac{6}{25}\div(\frac{2}{5})+5-(1-\frac{25}{12})]$

⇒ A = 60 × $[\frac{6}{25}\times(\frac{5}{2})+5-(\frac{-13}{12})]$

⇒ A = 60 × $[\frac{3}{5}+5 +(\frac{13}{12})]$

⇒ A = 60 × $[\frac{3}{5}+5+\frac{13}{12}]$

⇒ A = 60 × $(\frac{36+300+65}{60})$

⇒ A = 60 × $\frac{401}{60}$

⇒ A = 401

Sum of digits = 4 + 0 + 1 = 5