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SSC CHSL 2023 PYQ — Question 68

SSC CHSL - 09 March 2023 - Shift 4 • Quantitative Aptitude • Q68

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If A = 36÷18×536÷(3×4)\frac{36 \div 18 \times 5}{36 \div (3 \times 4)} and B = 5÷15×5+6×2−515÷5×25−2×3+6\frac{5 \div 15 \times 5 + 6 \times 2 - 5}{15 \div 5 \times 25 - 2 \times 3 + 6} then what is the value of (A + B)?

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 776/225.

 A = 36÷18×536÷(3×4)\frac{36 \div 18 \times 5}{36 \div (3 \times 4)}

A = 10/3

B = 5÷15×5+6×2−515÷5×25−2×3+6\frac{5 \div 15 \times 5 + 6 \times 2 - 5}{15 \div 5 \times 25 - 2 \times 3 + 6} 

B = ( 5 / 3 + 7 ) / 75

= 26 / 225 

A + B = 10 / 3 + 26 / 225

= ( 750 + 26 ) / 225

= 776 / 225