SSC Selection Post 2025 PYQ — Question 37

SSC Selection Post - Graduation Level - 28th July 2025 - Shift 3 • Quantitative Aptitude • Q37

If a = 0.25, b = -0.05, and c = 0.5, find the value of (a² – b² – c² – 2bc) / (a² – b² – 2ab – c²).

Show answer & explanation

Correct answer: A

Explanation

a = 0.25 = 1/4

b = −0.05 = −1/20

c = 0.5 = 1/2

(a² − b² − c² − 2bc) / (a² − b² − 2ab − c²)

Numerator -

= (1/4)² − (−1/20)² − (1/2)² − 2(−1/20)(1/2)

= 1/16 − 1/400 − 1/4 + 1/20

= (25 − 1 − 100 + 20)/400

= −56/400

= −14/100

Denominator -

= (1/4)² − (−1/20)² − 2(1/4)(−1/20) − (1/2)²

= 1/16 − 1/400 + 1/40 − 1/4

= (25 − 1 + 10 − 100)/400

= −66/400

(−56/400) ÷ (−66/400)

= 56/66 = 28/33