If (8x3 - 27y3) ÷ (2x - 3y) = (Ax2 + Bxy + Cy2), then the value of (2A + B - C) is:
Show answer & explanation
Correct answer: A
Explanation
Correct Answer is option 1 i.e. 5
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Concept |
Application |
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Formula: a3 - b3 = (a - b) (a2 + b2 + ab) |
[8x3 – 27y3] ÷ (2x – 3y) = Ax2 + Bxy + Cy2 ⇒ [(2x)3 – (3y)3] ÷ (2x – 3y) = Ax2 + Bxy + Cy2 Using the formula: ⇒ [2x – 3y] [(2x)2 + (3y)2 + (2x) × (3y)] ÷ (2x – 3y) = Ax2 + Bxy + Cy2 ⇒ [4x2 + 6xy + 9y2] = Ax2 + Bxy + Cy2 Comparing the coefficients: ⇒ A = 4, C = 9 and B = 6 Hence, 2A + B – C = 8 + 6 – 9 = 5 |