SSC Selection Post 2024 PYQ — Question 62

The correct answer is Option 1 i.e. ${{-1} \over 8}$.

8 tan A = 5

$sinA \over cosA$ = $5\over8$

Let sinA = 5k and cosA = 8k

${{8sinA -7cosA} \over 8sinA+11cosA}$

${{8(5k) -7(8k)} \over 8(5k)+11(8k)}$

${{40k -56k} \over 40k+88k}$

$-16 \over128$ = ${{-1} \over 8}$