If 7cos2 θ + 5sin2θ - 6 = 0, (0° < θ < 90°) then, what is the value of ?
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Correct answer: A
Explanation
The correct answer is Option 1 i.e .
⇒ 7cos2 θ + 5sin2θ - 6 = 0
⇒ 2cos2 θ + 5cos2 θ + 5sin2θ = 6
⇒ 2cos2 θ = (6 - 5)
⇒ cos2 θ = 1/2
⇒ θ = 45°
⇒ =
⇒ = .