SSC CGL 2023 PYQ — Question 65

SSC CGL - 14 July 2023 - Shift 1 • Quantitative Aptitude • Q65

If 7b - (1/4b) = 7, then what is the value of 16b2 + (1/49b2) ?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is Option 3 i.e. 120/7.

7b - 1/4b = 7

multiply both sides by 4/7

⇒ 7 × 4/7b - 1/4 × 4/7b = 7 × 4/7

⇒ 4b - 1/7b = 4

Now, squaring both sides

⇒ (4b - 1/7b)2 = 16

⇒ 16 b2 + 1/49 b2 - 2 × 4b × 1/7b = 16

⇒ 16b2 + 1/49b2 - 2 × 4/7 = 16

⇒ 16b2 + 1/49b2 = 16 + 8/7

⇒ 16b2 + 1/49b2 = 120/7