SSC Selection Post 2022 PYQ — Question 74

SSC Selection Post - Graduation Level - 8 Feb 2022 - Shift 3 • Quantitative Aptitude • Q74

If 6 cos2θ + cos θ = 2, 0° < θ < 90°, then the value of (cosec θ  + cot θ + tan θ) is: 

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 232{\sqrt3}.

6 cos2θ + cosθ = 2

⇒ 6 cos2θ + cosθ - 2 = 0

⇒ 6 cos2θ + 4cosθ - 3cosθ - 2 = 0

⇒ (3cosθ + 2)(2cosθ - 1) = 0

⇒ 2cosθ = 1

⇒ cosθ = 1/2

⇒ θ = 60°

Now, cosec θ + cotθ + tan θ

= cosec 60° + cot 60° + tan 60°

= 2/√3 + 1/√3 + √3 = 2√3