If 6 cos2θ + cos θ = 2, 0° < θ < 90°, then the value of (cosec θ + cot θ + tan θ) is:
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Correct answer: B
Explanation
The correct answer is option 2 i.e. .
6 cos2θ + cosθ = 2
⇒ 6 cos2θ + cosθ - 2 = 0
⇒ 6 cos2θ + 4cosθ - 3cosθ - 2 = 0
⇒ (3cosθ + 2)(2cosθ - 1) = 0
⇒ 2cosθ = 1
⇒ cosθ = 1/2
⇒ θ = 60°
Now, cosec θ + cotθ + tan θ
= cosec 60° + cot 60° + tan 60°
= 2/√3 + 1/√3 + √3 = 2√3