SSC CGL 2025 PYQ — Question 69

The correct answer is option 1 i.e. 10%.

$A = P \left( 1 + \frac{R}{100} \right)^n$

⇒ $6050 = 5000 \left( 1 + \frac{R}{100} \right)^2$

⇒ $\left( 1 + \frac{R}{100} \right)^2 = \frac{6050}{5000} = 1.21$

⇒ $1 + \frac{R}{100} = \sqrt{1.21} = 1.1$

⇒ $\frac{R}{100} = 1.1-1=0.1$

⇒ R = 10%