SSC CHSL 2025 PYQ — Question 69

SSC CHSL - 27 Nov 2025 - Shift 3 • Quantitative Aptitude • Q69

If 4x² + y² = 40 and xy = 6, find the value of 2x + y and 2x - y.

Show answer & explanation

Correct answer: B

Explanation

Given:

4x² + y² = 40

xy = 6

By the formula:

(2x + y)² = 4x² + y² + 4xy

(2x − y)² = 4x² + y² − 4xy

(2x + y)² = 4x² + y² + 4xy

= 40 + 4(6)

= 40 + 24

= 64

2x + y = 8

(2x − y)²= 4x² + y² − 4xy

= 40 − 24

= 16

2x − y = 4

2x + y = 8, 2x − y = 4