SSC CHSL 2024 PYQ — Question 55

The correct answer is option 3 i.e. 60°.

Given, $4sin^2\theta-4\sqrt3sin\theta+3=0$

The given expression can be written as $(2 \sin\theta - \sqrt{3})^2 = 0$

⇒ $2\sin\theta = \sqrt{3}$

⇒ $\sin\theta = \frac{\sqrt{3}}{2}$

⇒ $\theta$ = 60°