SSC CGL 2024 PYQ — Question 64

SSC CGL - 24 Sep 2024 - Shift 3 • Quantitative Aptitude • Q64

If 436P5 is divisible by 3, then the largest value of P is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 9.

A number is divisible by 3 if the sum of its digits is divisible by 3.

In the number 436P5, the sum of the digits = 4 + 3 + 6 + P + 5 = 18 + P

The possible values for P = 0, 3, 6, and 9

If P = 9 then 18 + P = 18 + 9 = 27 (divisible by 3)

Therefore, the largest value of P is 9.