If 4 cos2θ – 3sin2θ + 2 = 0, then the value of tanθ is (where 0 ≤ θ < 90o)
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e √(6).
| Understanding | Application |
| We can write 2 = 2( Sin2 + Cos2) |
4 cos2θ – 3sin2θ + 2 = 0 4 cos2θ – 3sin2θ + 2 ( sin2θ + cos2θ)= 0 4 cos2θ – 3sin2θ + 2sin2θ + 2 cos2θ = 0 6cos2θ - sin2θ = 0 6cos2θ = sin2θ Divide both sides by cos2θ. tan2θ=6 tanθ = |