SSC CHSL 2020 PYQ — Question 72

SSC CHSL - 20th October 2020 - Shift 1 • Quantitative Aptitude • Q72

If 4/3(x2 + (1/x2)) = 110 (2/3), find 1/9(x3 - (1/x3)), where x > 0.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e 84

⇒ (4/3)(x2 + (1/x2)) = 110(2/3)

⇒ (4/3){(x - 1/x)2 - 2} = 332/3

⇒ (x - 1/x)2 + 2= 83

⇒ (x - 1/x)2 = 81

⇒ x - 1/x = 9

⇒ (1/9){x3 - (1/x3)} = (1/9){(x - 1/x)3 + 3(x - 1/x)}

⇒ (1/9){(93 + 3 × 9} = (1/9)(729 + 27)

⇒ 81 + 3 = 84