If 4 - 2sin2θ - 5 cosθ = 0, 0°< θ < 90°. then the value of cosθ - tanθ is:
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Correct answer: D
Explanation
The correct answer is Option 4 i.e .
Given:
4 - 2sin2θ - 5cosθ = 0
Identity used:
sin2θ = 1 - cos2θ
Calculation:
⇒ 4 - 2sin2θ - 5cosθ = 0
⇒ 4 - 2 × (1 - cos2θ) - 5cosθ = 0
⇒ 4 - 2 + 2cos2θ - 5cosθ = 0
⇒ 2cos2θ - 5cosθ + 2 = 0
⇒ 2cos2θ - 4cosθ - cosθ + 2 = 0
⇒ 2cosθ × (cosθ - 2) - 1 × (cosθ - 2) = 0
⇒ (2cosθ - 1) × (cosθ - 2) = 0
⇒ cosθ = 1/2 and cosθ = 2
Rejecting cosθ = 2 as 0° < θ < 90°
So, cosθ will be 1/2
⇒ θ = 60°
Thus, The value of cosθ - tanθ
⇒ cos 60° - tan 60°
⇒ 1/2 - √3
⇒