SSC CPO 2020 PYQ — Question 109

SSC CPO - 25 Nov 2020 - Shift 1 • Quantitative Aptitude • Q109

If 4 - 2sin2θ - 5 cosθ  = 0, 0°< θ < 90°. then the value of cosθ - tanθ is:

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Correct answer: D

Explanation

The correct answer is Option 4 i.e   1−232\frac{1-2\sqrt3}{2}​​​​​​​​​​​​​​​​​​​​​.

Given:

4 - 2sin2θ - 5cosθ = 0

Identity used:

sin2θ = 1 - cos2θ

Calculation:

⇒ 4 - 2sin2θ - 5cosθ = 0

⇒ 4 - 2 × (1 - cos2θ) - 5cosθ = 0

⇒ 4 - 2 + 2cos2θ - 5cosθ = 0

⇒ 2cos2θ - 5cosθ + 2 = 0

⇒ 2cos2θ - 4cosθ - cosθ + 2 = 0

⇒ 2cosθ × (cosθ - 2) - 1 × (cosθ - 2) = 0

⇒ (2cosθ - 1) × (cosθ - 2) = 0

⇒ cosθ = 1/2 and cosθ = 2

Rejecting cosθ = 2 as 0° < θ < 90°

So, cosθ will be 1/2

⇒ θ = 60°

Thus, The value of cosθ - tanθ 

⇒ cos 60° - tan 60°

⇒ 1/2 - √3

⇒ 1−232\frac{1-2\sqrt3}{2}​​​​​​​