SSC CGL 2023 PYQ — Question 58

SSC CGL - 19 July 2023 - Shift 2 • Quantitative Aptitude • Q58

If(3y−3y)=5,\left ( 3y-\frac{3}{y} \right )=5, find the value of (y2+1y2)\left ( y^2+\frac{1}{y^2} \right ).

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. 439\frac{43}{9}.

⇒(3y−3y)=5,\left ( 3y-\frac{3}{y} \right )=5,

⇒ 3(y−1y)=53( y-\frac{1}{y} ) = 5

⇒ (y−1y)=53( y-\frac{1}{y} ) = {5\over3}

Squaring both sides

⇒ (y−1y)2=(53)2( y-\frac{1}{y})^2 = ({5\over3})^2

⇒ (y2+1y2−2×y×1y)=259{( y^2 + {1\over y^2} - {2\times y\times{1\over y}}}) = {25\over9}

⇒ (y2+1y2−2)=259{( y^2 + {1\over y^2} - {2}}) = {25\over9}

⇒ (y2+1y2)=259+2{( y^2 + {1\over y^2} }) = {25\over9} +2

⇒ (y2+1y2)=25+189{( y^2 + {1\over y^2} }) = {{25 + 18}\over9 }

⇒ (y2+1y2)=439{( y^2 + {1\over y^2} }) = {{43}\over9 }