SSC CHSL 2024 PYQ — Question 64

SSC CHSL - 05 July 2024 - Shift 1 • Quantitative Aptitude • Q64

If 3c2933k is divisible by both 5 and 11, where c and k are single digit natural numbers, then c + k = ______.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 6.

A number is divisible by 5 if its last digit is either 0 or 5

k must be either 0 or 5

A number is divisible by 11 if the difference between the sum of the digits at odd places and the sum of the digits at even places is either 0 or a multiple of 11.   

Odd place: 3 + 2 + 3 + k = 8 + k

Even place: c + 9 + 3 = c + 12

Difference = (8 + k) - (c + 12) = k - c - 4

If k = 5, the difference is 5 - c - 4 = 1 - c

So, 1 - c is a multiple of 11

If 1 - c = 0, then c = 1

c + k = 1 + 5 = 6

Therefore, the value of c + k is 6.