If 3 tan A = 4 and A is an acute angle, then the value of 4sinA + 3cosA is :
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Correct answer: D
Explanation
The correct answer is option 4 i.e. 5
3 tan A = 4
⇒ tan A = 4/3 = Height/Base
Hypotenuse = √(Height2 + Base2) = √(42 + 32) = √25 = 5
Now, 4sin A + 3cos A
= 4(4/5) + 3(3/5)
= 16/5 + 9/5
= 5
Therefore, the value of 4sin A + 3cos A is 5.