If 3 men and 2 women are seated in a row, how many seating arrangements are possible such that no woman is seated next to another woman?
Show answer & explanation
Correct answer: D
Explanation
Arrange 3 men first:
→ 3! = 6 ways
Now place 2 women so that no two sit together:
Gaps around men = _ M _ M _ M _ → 4 gaps
Choose 2 gaps for women:
→ ⁴C₂ = 6 ways
Arrange 2 women in selected gaps:
→ 2! = 2 ways
Total = 6 × 6 × 2 = 72
Hence, the correct answer is option 4.