If 3(cot²θ - cos²θ) = cos²θ, 0° < θ < 90°, then the value of (tan²θ + cosec²θ + sin²θ) is:
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Correct answer: B
Explanation
The correct answer is option 2 i.e. 61/12.
3(cot²θ - cos²θ) = cos²θ
3 cot²θ = 4 cos²θ
sin²θ = 3/4
sinθ = √3/2, θ = 60°
(tan²θ + cosec²θ + sin²θ)
= (3 + 4/3 + 3/4)
= 61/12