SSC CGL 2024 PYQ — Question 69

SSC CGL - 26 Sep 2024 - Shift 1 • Quantitative Aptitude • Q69

If 3(163−63)(162+62+Q)=30,\frac {3(16^3 - 6^3)} {(16^2 + 6^2 + Q)} =30, then find the value of Q.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 96.

a3 - b3 = (a - b)(a2 + ab + b2)

Now, 3(163−63)(162+62+Q)=30\frac {3(16^3 - 6^3)} {(16^2 + 6^2 + Q)} =30

⇒ (163−63)(162+62+Q)=10\frac {(16^3 - 6^3)} {(16^2 + 6^2 + Q)} =10

⇒ 163 - 63 = 10(162 + 62 + Q)

⇒ (16 - 6)(162 + 96 + 62) = 10(162 + 62 + Q)

⇒ 10(162 +96 + 62) = 10(162 + 62 + Q)

⇒ 162 + 96 + 62 = 162 + 62 + Q

⇒ Q = 96

Therefore, the value of Q is 96.