If 2x = 3y = 6z , then is 1/x + 1/y - 1/z equal to :
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Correct answer: C
Explanation
The correct answer is option 3 i.e. 0.
Let 2x = 3y = 6z = k
2 = k(1/x); 3 = k(1/y); and 6 = k(1/z)
So, k(1/z) = k(1/x) × k(1/y)
⇒ k(1/z) = k(1/x + 1/y)
⇒ 1/z = 1/x + 1/y
⇒ 1/x + 1/y - 1/z = 0