If 2cos2θ = 3(1- sinθ), 0° < θ < 90°, then what is the value of (tan2θ + cosec3θ - sec2θ)?
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Correct answer: C
Explanation
The correct answer is option 3 i.e. - 1.
2cos2θ = 3(1- sinθ)
2(1 + sinθ)(1- sinθ) = 3(1- sinθ)
sinθ = 1/2 = 30°
(tan2θ + cosec3θ - sec2θ) = (tan2 × 30° + cosec3 × 30° - sec2 × 30°)
= + 1 - 2
= - 1