If 29 December 1956 was a Saturday, then what was the day of the week on 16 January 1967?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. Monday.
1956 to 1966 = 10 Years (8 Ordinary Years and 2 Leap Years).
And, In 10 Years = 2 Leap years and 8 Ordinary Years.
Total odd days = 4 + 8 = 12.
12 odd days → 12/7 = 1 week and 5 odd days.
Then, 29 December 1966 will be Saturday + 5 = Thursday.
Now, the number of days between 29 December 1966 to 16 January 1967 = 2(December) + 16(January) = 18 days.
18 days → 18/7 = 2 weeks and 4 odd days. So, 16 January 1967 will be Thursday + 4 = Monday.