If 24√3x3 + 2√2y3= (2√3x + √2y)(Ax2 + Cy2 + Bxy), then (2A + √6B – C) is equal to:
Show answer & explanation
Correct answer: B
Explanation
Correct Answer is option 2 i.e. 10
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Application |
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24√3x3 + 2√2y3= (2√3x + √2y)(Ax2 + Cy2 + Bxy) 24√3x3 + 2√2y3 = 2√3Ax3 + 2√3Bx2y + 2√3Cxy2 + √2Ax2y + √2Bxy2 + √2Cy3 Comparing the coefficient: A = 12 and C = 2 2√3B + √2A = 0 ⇒ B = -2√6 Hence, (2A + √6B – C) = 2 × 12 + √6 × (-2√6) – 2 = 24 − 12 – 2 = 24 – 14 = 10 |