SSC CGL 2020 PYQ — Question 51

SSC CGL - 5th March 2020 Shift 2 • Quantitative Aptitude • Q51

If 20x2 — 30x + 1 = 0, then what is the value of 25x2 + (1)/(16x2)

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e 

Explanation:

20x2 - 30x + 1= 0

Dividing by x20x-30+1/x=0

20x+1/x=30

5x+1/4x=15/225x2 + (1)/(16x2)

= 25x2 + (1)/(16x2) +2 × 5x × 1/4x - 2 × 5x × 1/4x

= 25x2 + (1)/(16x2) + (5/2) - (5/2)

= (5x + 1/4x)2 - (5/2)

= (15/2)2 - (5/2)

= (225/4) - (5/2)
= (215/4) =