If 2(cosec239°- tan251°) -2/3(sin90°) – tan256° y tan234° = y/3, then the value of y is:
Show answer & explanation
Correct answer: B
Explanation
Correct Answer is option 2 i.e. 1
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Concept |
Application |
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Cosec x = Sec (90 – x) Tan x = Cot (90 – x) Tanx = 1/Cotx sec2x - tan2x = 1 |
2(cosec239°- tan251°) -2/3(sin90°) – tan256° y tan234° = y/3 ⇒ 2(cosec2(90 – 51)°- tan251°) - 2/3 – tan256° y tan2(90 – 56) = y/3 ⇒ 2(sec251°- tan251°) - 2/3 – tan256° y cot256 = y/3 ⇒ 2 – 2/3 – y = y/3 ⇒ 4/3 = 4y/3 ⇒ y = 1 |