If 2 cos²θ + 3 sinθ = 3 where 0° < θ <90 , then what is the value of sin²2θ + cos²θ + tan² 2θ + cosec² 2θ?
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Correct answer: A
Explanation
The correct answer is option 1 i.e. 35/6
2 cos²θ + 3 sinθ = 3
putting the value of θ = 30°
LHS = RHS
Now,
sin² 2θ + cos²θ + tan² 2θ + cosec² 2θ = sin² 60 + cos² 30 + tan² 60 + cosec² 60
